Question

What is the vertex of the graph of y = −1(x − 2)2 + 3?

(3,-2)
(-2,3)
(3,2)
(2,3)

Answer 1

the vertex form is y=a(x-h)²+k
the vertex is (h,k)
so

y=-1(x-2)²+3
compare to
y=a(x-h)²+k
2=h and 3=k
the vertex is (2,3)
4th option

Answer 2

(2,3)

Explanation:

An equation of the form

`a^(2)  + bx + c = 0`

can be expressed in the Vertex Form:

`y = a (x - h)^(2)  + k`

where the vertex is always:

(h, k)

The vertex is the lowest or highest point of the parabola.

When we compare the two functions:

`y = a (x - h)^(2)  + k`

`y = -1 (x - 2)^(2)  + 3`

We can see that

a = -1

h = 2

k = 3

So the vertex is:

(h, k) = (2, 3)

I hope this helps!