Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A(n) = –6 + (n – 1)(6)

Answer 1

1st term
A (1) = -6+(1-1)(6)
= -6 +0
= -6

4th term
A (4)= -6 +(4-1)(6)
=-6 + 18
= 12

10th term
A (10) =-6 +(10-1)(6)
=-6 + 54
=48.