Question

1. How many molecules of C₁₂H₂₂O₁₁ are in 179g of C₁₂H₂₂O₁₁?

Answer 1

`\qquad \quad \large {\pmb{ \frak { \mid {\overline{ \underline{\purple{ \bigstar \: Required \: Answer \: \bigstar}}}}}} \mid}\\`

We are given –

• Mass of C₁₂H₂₂O₁₁ is 179g. So, let's find molar mass and moles number of C₁₂H₂₂O₁₁.

`\qquad`
`\pink{\bf\longrightarrow { Molar \:mass \:of \:C₁₂H₂₂O₁₁ :-} }`

`\qquad`
`\bf \twoheadrightarrow 12* 12+1* 22+16* 11`

`\qquad`
`\bf \twoheadrightarrow 342`

`\qquad`____________________

Calculating the number of moles present in 179 g of C₁₂H₂₂O₁₁.

`\qquad`
`\purple{\sf\longrightarrow { No \:of \:moles = (Given \:mass)/(Molar\: mass)}}`

`\qquad`
`\bf \twoheadrightarrow (179)/(342)`

`\qquad`
`\bf \twoheadrightarrow \cancel{(179)/(342)}`

`\qquad`
`\purple{ \bf \twoheadrightarrow 0.523\: moles}`

• Avogadro number = 6.022×10²³

☀️No.Of Molecules –

=Moles × Avogadro number

= 0.523 × ( 6.02×10²³)

= 3.15 × 10²³

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