Register
Tan x =sin x/cos x. Therefore, tan(90-A) = A) 1/tan(90-A) B) 1/sin A C) 1/cos(90-A) D) 1/tanA
151k views
4 votes
Tan x =sin x/cos x. Therefore, tan(90-A) =

A) 1/tan(90-A)
B) 1/sin A
C) 1/cos(90-A)
D) 1/tanA

User JasonCG
by
7.4k points

1 Answer

3 votes
sin(90-A) = cos A
cos(90-A) = sin A

Therefore,

tan(90-A) = sin(90-A)/cos(90-A) = (cos A)/(sin A) = 1/(tan A)
User Joohyun
by
8.7k points
← Prev Question Next Question →

Related questions

User Nick Scottman
asked Jul 1, 2024 65.5k views
If tanA = 4/3 and sin B = 8/17 and angles A and B are in Quadrant I, find the value of tan(A+B).
Nick Scottman asked Jul 1, 2024
by Nick Scottman
8.0k points
1 answer
0 votes
65.5k views
User Jan Aka Uptech
asked May 20, 2024 234k views
If tana = 3/4 and cosb = 7/25, find the value of tan(a-b). a) -23/61 b) -5/33 c) 1/3 d) 33/5
Jan Aka Uptech asked May 20, 2024
by Jan Aka Uptech
8.6k points
1 answer
2 votes
234k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!