Question

Find the volume of a square pyramid with base edges of 48 cm and a slant

height of 26 cm.



A) 11,520 cm3


B) 23,040 cm3


C) 7,680 cm3


D) 768 cm3

Answer 1

The height of this pyramid will be:

√(26^2 - (48/2)^2) = 10cm

So the volume is: V = 1/3 * 48^2 * 10 = 7680 cm^3

Answer 2

Answer:- C)
`7,680\ cm^3`

Explanation:-

Given: Base edge of square pyramid a= 48 cm

Slant height square pyramid l =26 cm

Let h be the height of the right pyramid

Thus,

`h^2=l^2-((a)/(2))^2=26^2-((48)/(2))^2=676-576=100\\\\\Rightarrow\ h=√(100)=10`

The volume of square pyramid
`=(1)/(3)a^2h=(1)/(3)(48)^2(10)=7680\ cm^3`

Thus C is the right option.The volume of square pyramid=
`7,680\ cm^3`