Question

A certain bacteria is growing at a rate of 4 percent each day. If the culture of bacteria has 5,000 bacteria today, how many bacteria will be present 10 days from now?

Answer 1

Since we are given that the rate of growth of the bacteria is 4% then, the amount of bacteria is 1.04 times that of the amount the previous day. This can be mathematically expressed as,

A(t) = (Ao) x (1.04)^(t/n)

where A(t) is the amount after t days, Ao is the original amount, t is the number of days and n is the basis of the rate reported.

Substituting the known values,

A(t) = 5000 x (1.04)^(10/1)
A(t) = 7401.22

Thus, the amount of bacteria after 10 days is approximately equal to 7401.