Question

What is the magnification of a curved mirror if a 10.0 cm tall object is placed 8.00 cmfrom the mirror and produces an image 12.00 cm in front of the mirror?-0.6671.50-1.500.667

Answer 1

We will have that the magnification will be given by:

`m=-(v)/(u)`

That is:

`\begin{gathered} m=-(8cm)/(12cm)\Rightarrow m=-(2)/(3) \\ \\ \Rightarrow m\approx-0.667 \end{gathered}`

So, the magnification is approximately -0.667.