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A bag contains 3 red marbles and 4 blue marbles. then, 2 marbles are drawn from the bag, at random, "without replacement". if the first marble drawn is red, what is the probability that the second marble is blue

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3 + 4 +2 = 9 total marbles

If you pick a red one first and don't replace it that leaves a total of 8 marbles left

there are 4 blue marbles

so probability = 4/8, reduces to 1/2 probability of picking a blue marble

User Rahman Haroon
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