Question

A geometry class is asked to find the equation of a line that is parallel to y – 3 = −(x + 1) and passes through (4, 2). Trish states that the parallel line is y – 2 = –1(x – 4). Demetri states that the parallel line is y = –x + 6.

Answer 1

y - 3 = -(x + 1)
y - 3 = -x - 1
y = -x - 1 + 3
y = -x + 2....slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(4,2)...x = 4 and y = 2
sub and find b, the y int
2 = -1(4) + b
2 = -4 + b
2 + 4 = b
6 = b

ur parallel line is : y = -x + 6
or

y - y1 = m(x - x1)
slope(m) = -1
(4,2)...x1 = 4 and y1 = 2
sub
y - 2 = -1(x - 4)

they are both correct