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What is the simplified form of the quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the quantity of x plus 3?

2 Answers

5 votes
assuming the question looks like this:

(x+7)/6 - (x+5)/(x+3)

multiply by (x+3):

(x+7)(x+3)/6 - (x+5)

multiply by 6:

(x+7)(x+3) - 6(x+5)

expand:

x^2 + 10x + 21 - 6x - 30

collect like terms:

x^2 + 4x - 9

hope that helps :)
User Gabriel Bercea
by
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2 votes

Answer:

The quantity of x squared plus 4x minus 9, all over 6 times the quantity of x plus 3

Explanation:

Given expression,

The quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the quantity of x plus 3,


\implies (x+7)/(6)-(x+5)/(x+3)


=((x+7)(x+3)-6(x+5))/(6(x+3)) ( Subtraction of fractions ),


=(x(x+3)+7(x+3)-6x-30)/(6(x+3)) ( Distributive property )


=(x^2+3x+7x+21-6x-30)/(6(x+3))


=(x^2+4x-9)/(6(x+3)) ( Combine like terms ),

= The quantity of x squared plus 4x minus 9, all over 6 times the quantity of x plus 3

User Atlantis
by
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