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If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.
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Nov 5, 2018
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If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.
Mathematics
college
Das Jott
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Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t /
8St^2
Rewriting the squared terms in simplified form :
Width = 16 x S x S x t /
8 x S x t x t
Cancelling the like terms
Width = 16 x S /
8 x t
Cancelling the numeric terms :
Modify the values.
Addaon
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Nov 12, 2018
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Addaon
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