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The axis of symmetry for the function f(x)= -x^2-10x+16 x=-5

The axis of symmetry for the function f(x)= -x^2-10x+16 x=-5
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The axis of symmetry for the function f(x)= -x^2-10x+16 x=-5

User Deepak Yadav
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1 Answer

4 votes
Find the vertex:

x = 10/(-2) = -5! Yeah!
User Shmuly
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