Question

A 2300-kg truck is traveling down a highway at 32 m/s. What is the kinetic energy of the truck?

Answer 1

1177600 joules

Explanation:

Given:

m = 2300 kg

v = 32 m/s

We can calculate the kinetic energy using the following formula:

`E=(1)/(2)m\cdot v^2`

Replacing:

`\begin{gathered} E=(1)/(2)\cdot2300\cdot32^2 \\ E=1177600\text{ J} \end{gathered}`

The kinetic energy of the truck is 1177600 joules.