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A 2300-kg truck is traveling down a highway at 32 m/s. What is the kinetic energy of the truck?

User Sergey Narozhny
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1 Answer

20 votes
20 votes

ANSWER:

1177600 joules

Explanation:

Given:

m = 2300 kg

v = 32 m/s

We can calculate the kinetic energy using the following formula:


E=(1)/(2)m\cdot v^2

Replacing:


\begin{gathered} E=(1)/(2)\cdot2300\cdot32^2 \\ E=1177600\text{ J} \end{gathered}

The kinetic energy of the truck is 1177600 joules.

User Smyrnian
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