117k views
0 votes
What is the approximate value of X? Round to the nearest tenth.

What is the approximate value of X? Round to the nearest tenth.-example-1
User Jandot
by
7.6k points

2 Answers

5 votes
You have to use trigonometry.

To find the angle which is the fartest from the known angle, you use the SINE.

So 6*sin(50°) = 6*0,766 = 6*0,8 = 4,8 cm

Answer C
User Loler
by
9.4k points
2 votes

Answer

Find out the value of x.

To prove

By using the trignometric identity


sin\theta = (Perpendicular)/(Hypotenuse)

As given in the diagram.


\theta = 50 ^(\circ)

Perpendicular = x

Hypotenuse = 6

Put in the above identity


sin\ 50^(\circ) = (x)/(6)


sin\ 50^(\circ) = 0.77\ (Approx)

Put in the above


x = 6* 0.77

x = 4.6 cm (Approx)

Therefore Option (c) is correct .

User KitAndKat
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories