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What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

2 Answers

5 votes
Well, we need to solve the inequality in terms of x...

-3(6-2x)≥4x+12 carry out indicated multiplication on left side

-18+6x≥4x+12 subtract 4x from both sides

-18+2x≥12 add 18 to both sides

2x≥30 divide both sides by 2

x≥15, in interval notation:

x=[15, +oo)
User Smontanaro
by
6.6k points
3 votes

Answer:

x=[15, +oo) D

Explanation:

User Max Bileschi
by
6.1k points
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