Part 1
Find out the difference
2,051-1,808=243
therefore
243 students
Part 2
2008-2005=3
therefore
3 years
Part 3
Find out the average population
243/3=81 students per year
Part 4
I will assume that the relationship is linear
we have the ordered pairs
(2005,1,808) and (2008,2,051)
the slope is m=81
the linear equation is
y=mx+b
we have
m=81
point (2005,1,808) -------> year 2000 is For x=0
so
year 2005 ------> x=5
substitute
1,808=81(5)+b
b=1,808-405
b=1,403
therefore
y=81x+1,403
For the year 2000 the population is
y=1,403 students
Part 5
the equation of the population is
P=81t+1,403
Part 6
For the year 2013
t=2013-2000=13 years
substitute
P=81(13)+1,403
P=2,456 students