Question

In 2005, a school population was 1808. By 2008 the population had grown to 2051.

Answer 1

Part 1

Find out the difference

2,051-1,808=243

therefore

243 students

Part 2

2008-2005=3

therefore

3 years

Part 3

Find out the average population

243/3=81 students per year

Part 4

I will assume that the relationship is linear

we have the ordered pairs

(2005,1,808) and (2008,2,051)

the slope is m=81

the linear equation is

y=mx+b

we have

m=81

point (2005,1,808) -------> year 2000 is For x=0

so

year 2005 ------> x=5

substitute

1,808=81(5)+b

b=1,808-405

b=1,403

therefore

y=81x+1,403

For the year 2000 the population is

y=1,403 students

Part 5

the equation of the population is

P=81t+1,403

Part 6

For the year 2013

t=2013-2000=13 years

substitute

P=81(13)+1,403

P=2,456 students