143k views
4 votes
What is the PH of the acid lactic 0,20 M?

1 Answer

3 votes
dissociation constant of lactic acid:
K=1.38·10⁻⁴

C=0.20 mol/L

[H⁺]=√(KC)

pH=-lg[H⁺]=-lg{√(KC)}

pH=-lg{√(1.38·10⁻⁴·0.20)}=2.28

pH=2.28
User Mark Staff
by
8.6k points

No related questions found