Question

If m^6=3/y and m^5=y^2/6 then which of the following expresses m in terms of y?

Answer 1

m=(m^6)/(m^5)=(3/y)/(y^2/6)=(3/y)*(6/y^2)=18/y^3

Answer 2

m⁶ = 3/y and m⁵ = y²/6

m⁶ = m⁵.m¹ = m¹⁺⁵ = m⁶

m⁶ = m⁵. m = (y²/6).(m)

3/y = m(y²/6)
cross multiplication: m.y³ = 18
m=18/y³