Question

A spinner with sections "A," "B," "C," and "D” is spun, and a six sided die is rolled. What is the probability that the outcome will be "3-C?"1/121/242/173/14

Answer 1

This is a simple question to solve.

First Step: Once the spinner and the six-sided die are different objects, we will calculate their probability separately and then we will assemble both probabilities.

Second step: For the spinner, once we have A B C and D (4 sections in total) probable sections. We can represent the probability of section C as follows:

`P_{\text{sectionC}}=\frac{\text{number\_of\_sections\_we\_are\_interested}_{}}{\text{total\_number\_of\_sections}}=(1)/(4)`

Third step: For the six-sided die we have 1, 2, 3, 4, 5 and 6 (6 sides in total). We can represent the probability we have just side 3 as follows:

`P_(side3)_{}=\frac{\text{number\_of\_sides\_we\_are\_interested}_{}}{\text{total\_number\_of\_sides}}=(1)/(6)`

Fourth step: Now the probability to get side 3 and section C can be represented as a multiplication as follows: