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What are the solutions of the equation: z2 - 12z + 36 = 0? A. -6, 6 B. 6, 6 C. 6, -6 D. -6, -6
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What are the solutions of the equation: z2 - 12z + 36 = 0? A. -6, 6 B. 6, 6 C. 6, -6 D. -6, -6

User Neomib
by
8.3k points

2 Answers

3 votes
Option B is correct.

Step-by-step explanation:
z^2 -12z+36 =0
z^2 -6z-6z +36=0
z (z-6) -6 (z-6)=0
(z-6)(z-6)=0

(z-6) =0
z= 6
Again,

(z-6) =0
z= 6
So, option B is the correct one.
User Johannes Gontrum
by
7.7k points
4 votes
B 6, 6
Since the equation can be changed to (z-6)^2 = 0
User Yulanggong
by
8.4k points
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