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Calcium chloride is often used to de-ice roads in the winter. What volume would 15.7 g calcium chloride occupy? (Density = 2.50 g/cm^3)

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To determine this all you would need to do is rearrange the equation for density and solve for the value of volume. Then plug in the numerical values into the equation and solve for v.

D = m/v
Dv = m
V = m/D
V = 15.7 g/2.50 g/cm^3.
V = 6.28 ml.
User Tom Halladay
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