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How many total oxygen (O) atoms are present in the reactants side of equation C2H5OH + 3O2 = 2CO2 + 3H2O
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How many total oxygen (O) atoms are present in the reactants side of equation C2H5OH + 3O2 = 2CO2 + 3H2O

User Ahmad Farid
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2 Answers

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That would be SEVEN, ethanol has 1 and oxygen contribute six (2 x 3)
User Gaby
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There are seven oxygen atoms present on the reactants side of the equation.
User Sabareesh
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