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A penny falls from a windowsill which is 25.0 m above the sidewalk. How much time does a passerby on the sidewalk below have to move out of the way before the penny hits the ground?
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A penny falls from a windowsill which is 25.0 m above the sidewalk. How much time does a passerby on the sidewalk below have to move out of the way before the penny hits the ground?

User Jiovanny
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2 Answers

7 votes

Answer:2.26

Step-by-step explanation:

User MirekE
by
8.5k points
4 votes
You need to know the formula:

25 = 1/2 * g * t^2

t = √(50/g) = 2.258 s, where I use g = 9.8 m/s^2
User Jarchuleta
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