Question

The length of a rectangle is 120 m. The diagonal measures 130 m.

Use this information to find the values of the perimeter and area of the rectangle.

Perimeter of the rectangle: ____ meters

Area of the rectangle: ____ square meters

Answer 1

Width of the rectangel is found by using Pythagoras theorem

w^2 = 130^2 - 120^2 = 2500

width w = sqrt 2500 = 50 m

Perimeter of rectangle = 2*120 + 2*50 = 340 m

Area of the rectangle = 50 * 120 = 6000 m^2

Answer 2

Diagonal is sqrt (l^2 +W^2)

Length = 120

Diagonal = 130

130 = sqrt ( 120^2 +w^2)

130^2 = w^2 +120^2

16900 = w^2 + 14400

W^2 = 2500

w = sqrt(2500)

W=50

Perimeter = 240 +100 = 340 meters

Area = 120 x 50 = 6000 sq meters