Question

3a+2b=8

\displaystyle a = 6b + 6 a=6b+6

Answer 1

First, let's write it like this:

`3a+2b=8`
Subtract
`2b` from both sides.

`3a+2b-2b=8-2b`

`3a=8-2b`
Divide both sides by 3.

`(3a)/(3)=(8-2b)/(3)`

`a=(8-2b)/(3)`

Now that we know what's the value of
`a`, let's find the value of
`b`

`3\cdot (8-2b)/(3)+2b=8`
Let's take the first part.

`3\cdot (8-2b)/(3)`
Multiply the fractions.

`=(\left(8-2b\right)\cdot \:3)/(3)`
Cancel the common factor, which is 3.

`=8-2b`
We would be left with.

`=8-2b+2b`
Add like terms.

`=8`
We would be left with.

`8=8`
Subtract 8 from both sides.

`8-8=8-8`

`0=0`

This tells us that
`b` can be any number.

Let me know if you need any help!
Thanks!
-TetraFish