Question

A block of mass 10 kg slides down an inclined plane that has an angle of 30. If the inclined plane has no friction and the block starts at a height of 2 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2.

Answer 1

No friction present means: Ek = Ep

So Ek = mgh = 10 * 9.8 * 2 = 196 J

Answer 2

E = 196 joules

Step-by-step explanation:

It is given that,

Mass of the block, m = 10 kg

At the top, the block will have only potential energy which is given by :

`P=mgh`

At the bottom of the inclined plane, it will have only kinetic energy which is given by :

`E=(1)/(2)mv^2`

Applying the conservation of energy as :

`E=(1)/(2)mv^2=mgh`

`E=10\ kg* 9.8\ m/s^2* 2\ m`

E = 196 joules

So, the block will have 196 joules of kinetic energy when it reaches the bottom. Hence, this is the required solution.