116k views
2 votes
it takes 70 oz of grass seed to seed 2800ft of lawn. at this rate, how much would be needed for 3600 ft of lawn?

User Sebin
by
8.7k points

1 Answer

3 votes
Find the multiplier to get from 2800ft to 3600ft. Multiply the weight of seed required for 2800ft by this multiplier for your answer.
3600/2800=9/7
70*9/7=90 oz
User Samuel Ramzan
by
7.9k points

Related questions

1 answer
0 votes
16.3k views
1 answer
1 vote
58.5k views