Question

What is the length of EF in the right triangle below?

a: 22
b: 505
c. 217
d. Square root 17
e: square root 505
f: 7

Answer 1

\sqrt(217)

Explanation:

(19)^2=(12)^2

361 - 144 + 217

\sqrt(217)

Answer 2

`√(217)units`

Explanation:

Given : A right angled triangle EFD

Hypotenuse = ED=19 units

Base = DF =12 units

Perpendicular = EF

Solution:

To find length of EF we will use Pythagorean Theorem:

`(Hypotenuse)^(2)=(Perpendicular)^(2)+(Base)^(2)`

`ED^(2)=EF^(2)+DF^(2)`

`19^(2)=EF^(2)+12^(2)`

`361=EF^(2)+144`

`361-144=EF^(2)`

`217=EF^(2)`

`√(217) =EF`

Thus the length of EF is
`√(217)units`