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JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.

JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.-example-1
User Almel
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6.1k points

1 Answer

6 votes
If you divide each diagonals by 2, you get the sides of the right triangle that makes the rhombus. The hypothenuses are the sides of the rhombus.

Apply the Pithagorean Theorem

Side = √(KM/2)² + (JL/2)² = √(10/2)² + (24/2)² = √5² + 12² = √25+144 = √169 = 13 (cm?)

P = Side*4 = 13*4 = 52 (cm?)
User Domen
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5.7k points
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