Question

If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (P=2w+2l)

Answer 1

To find the dimensions of a rectangular rug given its perimeter and the length being three feet more than the width, use the formula for the perimeter of a rectangle. Solve the equation for the width and calculate the length by adding three to the width. The width of the rug is 5 feet and the length is 8 feet.

Step-by-step explanation:

To find the dimensions of the rectangular rug, let's assume that the width is represented by 'w'. Since the length is three feet more than the width, we can express the length as 'w+3'.

The perimeter of a rectangle is given by the formula P = 2w + 2l, where P represents the perimeter, w represents the width, and l represents the length.

Substituting the given values into the formula, we have 26 = 2w + 2(w + 3).

By simplifying the equation, we can solve for 'w' and find the width. Then, we can calculate the length by adding three to the width.

After performing the calculations, we find that the width of the rug is 5 feet and the length is 8 feet.

Answer 2

You have the lenght that is 3w, so lenght is the third part and the width the first part.

You assign the value 3 to l and the value 1 to w

Of course, you have to do the "semiperimeter" or you'll get double sides.

Semiperimeter = 26/2 = 13 ft.

You sum the parts

3+1 = 4

13/4 = 3,25 ft. (1 part)

3,25*1 = 3,25 ft. (Widht)

3,25*3 = 9,75 ft. (Lenght)

You can solve it even as an equation

You put x the lenght, the width is 3x

x+3x = 13

4x = 13

x = 3,25

w = 3*3,25 = 9,75