Question

At intermission, Xavier sold refreshments. Of the items he had, 1/5 were granola bars and 1/2 the remaining items were containers of popcorn. The rest were divided equally among apples, rice cakes, and containers of yogurt. Xavier sold the 8 apples he had. How many items did he originally have?

Answer 1

The answer to this word problem is 60 items, if you want to see how I solved it, just let me know.

Answer 2

Answer: There are 80 items he originally have.

Explanation:

Since we have given that

Part of refreshments were granola =
`(1)/(5)`

Part of refreshments were popcorns =
`(1)/(2)`

Remaining part would be

`1-((1)/(5)+(1)/(2))\\\\=1-(7)/(10)\\\\=(10-7)/(10)\\\\=(3)/(10)`

Since rest were divided equally among apples, rice cakes, and yogurt.

Number of apples sold = 8

Let the total number of items be 'x'.

According to question, it becomes,

`(3)/(10)* (1)/(3)x=8\\\\(x)/(10)=8\\\\x=80`

Hence, there are 80 items he originally have.