Question

Suppose the population of a town is 567 in 2001. The population decreases at a rate of 1.5% every year. What will be the population of the town in 2010? Round your answer to the nearest whole number.

1.) A is congruent to 487 people
2.) A is congruent to 467 people
3.) A is congruent to 495 people
4.) A is congruent to 465 people

Answer 1

The answer is 495 people.

Explanation:

In 2001, the population of the town is = 567

The population decreases at a rate of 1.5% every year.

This is an exponential decrease, so we can write the expression as :

`((1-.015)^9)(567)`

=
`((0.985)^9)(567)`

`0.87282*567` = 494.888 ≈ 495

Therefore, the answer is 495 people.

Answer 2

for the formula is

Y = starting population x (1-rate of change)^number of years

2010-2001 = 9

Y= 567 x (1-0.015)^9 = 494.89, round up to 495 people