Answer:
4x-5y=5
Explanation:
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)?
4x-5y=5
5x+4y=37
4x+5y=5
5x-4y=8
from the graph given , the slope of a graph becomes
S=y2-y1/(x2-x1)
Slope=10-0/(-8-0)
slope=-10/8
for a line that is perpendicular
perpendicular lines=-1/m
negative inverse of the slope
8/10
equation of the line that passes through the point (5,3) becomes
y-y1=m(x-x1)
y-3=8/10(x-5)
5(y-3)=4(x-5)
5y-15=4x-20
5y=4x-20+15
4x-5y=5 A