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What is the 7th term in the geometric sequence in which a10 is 9 and a13 is -72?

a. 2B. - 1/8C. - 9/8D. 1/4

1 Answer

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recall, a geometric series has this form with constants A for n=0, and k, the ratio of two consecutive terms n/(n+1)

a_n =A*k^n

you are given two values, for n=13 and n=10, put both into the equation


9=A*k^(10)

-72=A*k^(13)


Two equations with two unknown values A and k, you can solve for those.

Solving both for A,

A= (9)/(k^(10)) = (-72)/(k^(13))



k=-2

A= (9)/(1024)

The general equation for the series is then,

a_n= (9)/(1024)(-2)^n

use n=7
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