Question

a gas container in a thick walled balloon. when the pressure changes from __kPa to 114kpa, the volume changes from 0.654L to 1.32 L and the temperature changes from 596 K to 715 k

Answer 1

191.80 kPa

Step-by-step explanation:

Answer 2

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1/T1 = P2V2/T2

P1 = P2V2T1/T2V1

P1 = (114)(1.32)(596)/(715)(.654)

P1 = 191.80 kPa