Question

A stone is thrown straight upward and reaches a maximum height of 32.3 m above itslaunch point. What was the initial speed with which the stone was thrown upwards?Answer:m/s

Answer 1

Answer:

The initial speed = 25.16 m/s

Step-by-step explanation:

The maximum height, H = 32.3 m

The initial speed, u = ?

The formula for the maximum height of a projectile is:

`H=(u^2)/(2g)`

Substitute H = 32.3m and g = 9.8 m/s² into the formula and solve for u

`\begin{gathered} 32.3=(u^2)/(2(9.8)) \\ \\ u^2=32.3(2)(9.8) \\ \\ u^2=633.08 \\ \\ u=√(633.08) \\ \\ u=25.16\text{ m/s} \end{gathered}`

The initial speed = 25.16 m/s