The diagram looks really off, so I'm assuming ( ( and (( (( are equal.
First off, AFD is 114 degrees, and is split into three angles, two of them being equal to 31 (AFB and CFD = (( ) and the other one needed to be found.
114 = 2(31) + x
114 = 62 + x
52 = x
Therefore, (( is 52 degrees. Now since AFE has two (( and two (, use this expression to find AFE.
52(2) + 31(2)
104 + 62
166
Therefore, AFE is equal to 166 degrees.