Question

Use the drawing tools to form the correct answer on the graph.Graph this function.f(1) =-2Drawing ToolsSelectPointLineClick on a tool to begin drawing.-10-8-6-210-86-42--6f(x)24Undo68Reset10

Answer 1

To graph a linear function, the y and x-intercepts are always good points, then, let's find that points and do our line.

I'll start with the y-intercept because it's the easier one, it's the value of y when x = 0, then

`\begin{gathered} f(x)=(3)/(4)x-2 \\ \\ f(0)=(3)/(4)\cdot0-2 \\ \\ f(0)=-2 \end{gathered}`

Then the line pass through the point (0,-2).

Now let's find the x-intercept (zero or root of the function), that's the value of x when y = 0

`\begin{gathered} f(x)=(3)/(4)x-2 \\ \\ 0=(3)/(4)x-2 \\ \\ (3)/(4)x=2 \\ \\ x=(2\cdot4)/(3) \\ \\ x=(8)/(3) \\ \\ x=2.67 \end{gathered}`

If the point (2.67, 0) is too hard to plot, we can also use the point when x = 4

`\begin{gathered} f(x)=(3)/(4)x-2 \\ \\ f(4)=(3)/(4)\cdot4-2 \\ \\ f(4)=3-2 \\ \\ f(4)=1 \end{gathered}`

A much easier point!

Plot those points:

Now do the line!