Question

∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?

Answer 1

as the angles are complementary sin A = cos B and sin B = cos A

so sin A + sin B = 0.55 + 0.83 = 1.38

Answer 2

`sin(A)+sin(B)=1.38`

Explanation:

Let

A, B and
`90\°` the measures of the angles in a right triangle

we know that

`m<A+m<B=90\°` ------> by complementary angles

so

`sin(A)=cos(B)`

`sin(B)=cos(A)`

In this problem we have

`cos(A)=0.83`

`cos(B)=0.55`

therefore

`sin(A)=0.55`

`sin(B)=0.83`

`sin(A)+sin(B)=0.55+0.83=1.38`