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Initially a beaker contains 225.0 ml of a 0.350 M MgSO4 solution. Then 175.0 ml of water are added to the beaker. Find the concentration of the final solution. What is the volume?

User Sunmat
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2 Answers

5 votes
Final volume is 400 mL

The moles in MgSO4 is 0.00788 mL

The new concentration is 0.197
User LaurentY
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6 votes

Answer : The concentration of final solution is, 0.197 M and the final volume of solution is, 400 ml

Solution :

First we have to calculate the final volume of solution.

Final volume of solution = Volume of
MgSO_4 + Volume of water added

Final volume of solution = 225.0 ml + 175.0 ml = 400 ml

Now we have to calculate the concentration of final solution.

Formula used :


C_1V_1=C_2V_2

where,


M_1 = concentration of
MgSO_4 solution = 0.350 M


V_1 = volume of
MgSO_4 solution = 225.0 ml


M_2 = concentration of final solution = ?


V_2 = volume of final solution = 400 ml

Now put all the given values in the above formula, we get the concentration of final solution.


(0.350M)* (225.0ml)=C_2* (400ml)


C_2=0.197M

Therefore, the concentration of final solution is, 0.197 M

User KingPin
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