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5 votes
What is the period of y=3cot(4x−3π)

2 Answers

5 votes

Answer:

π/4 or 0.78 in simplified or alternative form

absolute value of any number is always positive

User TomVW
by
7.5k points
3 votes
Hello!

hint: we can rewrite your function as below:

3/tan(4x−3π) = 3(1+tan4xtan3π)/tan4x−tan3π =

=3/tan(4x) = 3cot(4x)

now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

"4P=π"


Hope this Helps! Have A Wonderful Day! :)
User Russ Egan
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8.3k points