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2 votes
What is the area of this triangle?

A.) A=1/2(y3-y2)(x3-x1)
B.) A=1/2(y3-y1)(x3-x1)
C.) A=1/2(y3-y1)(x2-x1)
D.) A=1/2(y2-y1)(x3-x1)
E.) A=1/2(y2-y1)(x2-x1)

What is the area of this triangle? A.) A=1/2(y3-y2)(x3-x1) B.) A=1/2(y3-y1)(x3-x1) C-example-1
User Mishu
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2 Answers

3 votes
The answer is D.) A=1/2(y2-y1)(x3-x1).
Step-by-step explanation:
Area of a triangle equals side×height.
In this case height is x3-x1, and side y2-y1.
User Massimiliano
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8.3k points
5 votes

Answer:

Option D is correct

Step-by-step explanation:


\text{Given a triangle whose vertices are }(x_1, y_1), (x_1, y_2) , (x_3, y_3)

we have to find the area of triangle.

As we know area of triangle can be calculated by the formula


(1)/(2)* base* height

Base of triangle is the line joining the coordinates
(x_1, y_1), (x_1, y_2) whose length is =
(y_2-y_1)

Now height of triangle is the perpendicular line from the vertex
(x_3, y_3) whose length is
(x_3-x_1)

Hence, area of triangle is


(1)/(2)* (y_2-y_1)* (x_3-x_1)

Option D is correct

User FelHa
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8.2k points