Question

I would like someone to help me with this question - thx

Answer 1

Hello Gary!

Let slant height be s
Height = 38yd. = h
Side = 42yd. = a

S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.

Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²

In Short, The Correct Answer would be: Option "D". 3647 yd^2

Because: Base edge = 42 and Height = 38

So then, AL=a√a^2+4h^2=42·√42^2+4·38^2≈3646.99328. (3647 rounded up)

AL≈3646.99


Hope this Helps! Have A Wonderful Day! :)

Answer 2

First find the slope height

h^2 = 38^2 + 21^2

43.42 yds

lateral area = 4 * area of each triangle = 4 * 1/2 * 42 * 43.42 = 3647 yd^2

It's D