162k views
3 votes
The length of a rectangle is 6 m longer than its width. If the perimeter of the rectangle is 32 m , find its area.

User Hady
by
8.3k points

1 Answer

4 votes
Standard calculation for Perimeter is 2L+2W=P or 2(L+W)=P
As we have the totals for the perimeter at 32m and know the lenght is 6m longer than width we can build an equation to find W.

2(L+W)=Perimeter
2(x+x+6)=32
2(2x+6)=32
2x+6=32/2
2x+6=16
2x=16-6
2x=10
x=10/2
x=5

Now we have the width of 5m. As length is 6m longer than width means we add 6m to 5m to determine length

L=W+6
L=5+6
L=11

To determine if your calculations are correct place your L and W answers into original eqution to determine perimeter

2(11+5)=32
2(16)=32
32=32

Yes, it is found correct. Now to find the Area using the standard formula for Area. Area=L*W or A=LW

A=(11)(5)
A=55

Area = 55sq m

User Jente Rosseel
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories