Question

A student sets up two reactions. reaction 1 uses 0.170 mol/l of reactant, and reaction 2 uses 0.400 mol/l of reactant. how many times faster is reaction 2 compared to reaction 1?

Answer 1

[Rate]2 = 2.35[Rate]1

Step-by-step explanation:

Rate of reaction is given by:

Rate1= k[reactants]1= k[0.170moles]

Rate2= K]reactants]2= k[0.400moles]

Rate2 ÷ Rate1

[Rate]2/[Rate]1= 2.35

[Rate]2= 2.35[rate]1

Answer 2

In chemical reaction dynamics, the rate of the reaction can take different forms depending on the type. If we are to take this reaction as a first-rate reaction then, the rate is dependent to the concentration of the reactant.
n = 0.400 molL / 0.170 mol/L
n = 2.35 times
Thus, the second rate is 2.35 times the 1st rate.