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Calculate the efficiency for each machine, then answer the question. Machine A has an input work of 1,000 J and an output work of 250 J. Machine B has an input work of 500 J and an output work of 350 J. Machine C has an input work of 200 J and an output work of 150 J. Which machine is the most efficient?

2 Answers

3 votes
Machine C. Machine A has an efficiency of 250/1000 = 0.25 = 25%, Machine B's efficiency is 350/500 = 0.7 = 70% and Machine C has an efficiency of 150/200 = 0.75 = 75%.
User Rawwar
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8.6k points
5 votes

Step-by-step explanation:

Efficiency is defined as the measure of amount of work done by a system.

Mathematically,
Efficiency = (Energy output)/(Energy input) * 100

  • For machine A efficiency will be as follows.

Efficiency =
(Energy output)/(Energy input) * 100

=
(250 J)/(1,000 J) * 100

= 25%

  • For machine B efficiency will be as follows.

Efficiency =
(Energy output)/(Energy input) * 100

=
(350 J)/(500 J) * 100

= 70%

  • For machine C efficiency will be as follows.

Efficiency =
(Energy output)/(Energy input) * 100

=
(150 J)/(200 J) * 100

= 75%

Thus, we can see that efficiency is maximum in machine C, therefore, machine C is the most efficient.

User Jamie Cockburn
by
8.3k points