Question

How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated? Please help if anyone can !! :) 12 points

OPTIONS:
A.) 64
B.) 100
C.)
125

Answer 1

repeated
the lowest first digit can be 2
hmm, 5 numbers
the smallest number is 211
1 cannot be used for the first number, leaving 4 choices for the first number
the last 2 numbers can be any of the 5 numbers so 5 choices each for each of those slots
so
4*5*5=100
there are 100 numbers

B is answer

Answer 2

100

B is correct

Explanation:

If three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9

Here we have total number of digits are 5

We need to make 3-digit number which is greater than 200

First digit must be 2 or greater than 2

From list of number 1,2,6,7,9

Four numbers are greater than equal to 2

For 1st place total number of possibility = 4

For 2nd place number of possibility = 5

For 3rd place number of possibility = 5

Total numbers of which are greater than 200 = 4 x 5 x 5

= 100

Hence, 100 three-digit number greater than 200