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How can you write the expression with rationalized denominator?

How can you write the expression with rationalized denominator?-example-1

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( √(3)- √(6) )/(√(3)+√(6)) = ( (√(3)- √(6))(√(3)- √(6)) )/((√(3)+√(6))(√(3)- √(6))) = ((√(3)- √(6))^2)/(3-6)= (3-2 √(18)+6 )/(-3) = (9-6 √(2) )/(-3)= \\ \\ = (3(3-2 √(2)) )/(-3)= ((3-2 √(2)) )/(-1)=-(3-2 √(2) )=-3+2 √(2)

Hope this helps
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